(3x-2)(9x^2+6x+4)=9x(3x^2-2)-8

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Solution for (3x-2)(9x^2+6x+4)=9x(3x^2-2)-8 equation: 



(3x-2)(9x^2+6x+4)=9x(3x^2-2)-8

We move all terms to the left:

(3x-2)(9x^2+6x+4)-(9x(3x^2-2)-8)=0



We calculate terms in parentheses: -(9x(3x^2-2)-8), so:

9x(3x^2-2)-8

We multiply parentheses

27x^3-18x-8

We do not support expression: x^3

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